Since there can be <-ℓ, ℓ> orientations and since the orbital type f has ℓ = 3, we should have 7 possible orientations with 2 spins, so $7 imes 2 = 14$, so I thought the correct answer was D (14).

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However, I got it wrong and the correct answer is marked as C (2). Is it an error in the test, or am I missing something?

You"re correct that there are seven possible spatial orientations for an f-type orbital, and hence seven possible orbitals in one f-type sub-shell. However, the question specifically asks for the maximum number of electrons in one such orbital, and

*any*single atomic orbital, regardless of the sub-shell type specified by $l$, can only hold two electrons. This is by virtue of the Pauli exclusion principle. Fourteen would be the maximum number of electrons across an entire f-type sub-shell, but the question only asks about one orbital.

The question specifically ask that no.of electron an orbital of f subshell can hold.... As we know that f subshell contain 7 orbital and each orbital can hold maximum 2 electons so correct answer would be 2..we can simply understand this by taking the real life example imagine that there is house named f which consists of 7 rooms so similarly in this case house is a subshell and each room is an orbital... Thank you,

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