We’re being asked tocalculate the massive of barium sulfate (BaSO4)formed in the reaction of100.0 mL the 0.100 M BaCl2 solution and also 100.0 mL of 0.100 M Fe2(SO4)3.
You are watching: How many moles of barium sulfate are produced from 0.100 mole of barium chloride?
For this problem, we should do the adhering to steps:
Step 1:Determine the commodities of the reaction.
Step 2:Write and balance a chemical equation for the provided reaction.
Step 3:Determine the limiting reactant and also calculate the massive of BaSO4 produced.
Step 1:Since BaCl2 and also Fe2(SO4)3 areionic compounds, they form ions as soon as dissociating in water.The dissociation the the 2 compounds is together follows:
The chloride ion, Cl–, has actually a charge of–1. Barium is from team 2 therefore it has actually a charge of+2:
BaCl2(aq)⇌Ba2+(aq) + 2Cl–(aq)
The sulfate ion, SO42–, has a fee of–2. Steel then has a charge of+3:
Fe2(SO4)3(aq)⇌2 Fe3+(aq) + 3SO42–(aq)
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What mass of barium sulfate can be created when 100.0 mL the a 0.100-M systems of barium chloride is mixed with 100.0 mL the a 0.100-M solution of iron(III) sulfate?
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Our data shows that this trouble or a nearby variation to be asked in Chemistry: an Atoms an initial Approach - Zumdahl Atoms first 2nd Edition. You can additionally practice Chemistry: an Atoms first Approach - Zumdahl Atoms first 2nd Edition practice problems.
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