The oxidation variety of chlorine have the right to be determined by identifying an initial the oxidation numbers of oxygen and Na. Oxygen has a charge of -2 and has a total of -8. Na has +1. To do the full zero, Cl has to have a fee of +7. 

6) +1

Explanation:

The rules to identify oxidation number are

a) The oxidation number of alkali metals is +1 (except in super oxides or peroxides).

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b) the oxidation number of oxygen is -2 (except in super and peroxide or compounds through fluorine or v itself)

1) the oxidation number of chlorine in the reactant state: KClO₃:

+1 + x + 3(-2) = 0

x = oxidation number of chlorine =+5

2) The oxidation variety of oxygen in the reactant state: -2 together it is a normal oxide.

3) The oxidation number of potassium in the reactant state: +1

4) The oxidation variety of chlorine in the product state: -1

5 The oxidation number of oxygen in the product state: 0

The compound with itself.

6) The oxidation number of potassium in the product state+ +1 (alkali metal)


Answer- The correct choice of answer the end of all would certainly be choice C.

Explanation

The given substance magnesium chloride made out of mix of chlorine and also magnesium is a compound. Whereby magnesium has actually two hopeful ions and also chlorine has two negative ions which trigger the reaction.

Hence the oxidation of the 2 positive ions of Magnesium bring away place and reduction of the negative Ion chlorine has to offer attract and stabilize each various other by creating the compound.


second, fourth, and fifth one

Explanation:

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This is a three-part question

Answers:

a) The oxidation variety of chlorine in bleach (NaOCl) is +1.b) Yes, this is a oxidization reactionc) The percen yield is 56.8%

Explanation:


1) part (a) What is the oxidation number of chlorine in bleach (NaOCl)?

a) dominance one: In a neutral compound the amount of the oxidation claims is zero.

Since NaOCl is a neutral compound the amount of the oxidation states of Na, O and also Cl is 0.

b) rule two: since Na is one alkaline metal, its oxidation state is +1

c) rule three: the most common state that oxygen, other than in peroxides, is -2.

Then,

Na: +1O: -2Cl: x

sum = +1 - 2 + x = 0 ⇒ x = 2 - 1 = 1

Conclusion: the oxidation state the NaOCl is +1.

2) component (b) Is this reaction over redox?

In a oxidation reaction the oxidation claims of some substances rise (get oxidized) and also the oxidation states of part substances decrease (get reduced).

The reaction is represented by the chemical equation given:

NaOH (aq) + Cl₂ (g) → NaOCl (aq) + NaCl (aq) + H₂O (l)

Since the chlorine gas (Cl₂) is a molecule of just chlorine atoms, the oxidation state is zero, and since chlorine is creating compounds ~ above the right side (NaOCl and NaCl) girlfriend can automatically conclude that the oxidation state of chlorine changed, and also this is a redox reaction.

In fact:


Oxidation state that Cl in Cl₂: 0Oxidation state the Cl in NaOCl: +1 (previously determined)Oxidation state of Cl in NaCl: -1 (becasue Na has actually oxidation state +1 and so +1 - 1 = 0).

Therefore, chlorine is gift oxidized (its oxidation state increases from 0 come +1) and also is also being decreased (its oxidation state is lessened from 0 come -1), and also this is a oxidation reaction.

3) component (c) What is the percent productivity of this reaction?

a) chemistry equation (given)

NaOH (aq) + Cl₂ (g) → NaOCl (aq) + NaCl (aq) + H₂O (l)

b) Theoretical mole ratio:

2 mol Cl₂ (g) : 1 mol NaOCl (aq)

c) transform 83.0 g that chlorine gas to moles:

moles = fixed in grams / molar massmolar fixed of Cl₂(g) = 79.906 g/molmoles = 83.0 g / 79.906 g/mol = 1.039 mol Cl₂(g)

d) recognize the theoretical yiedl utilizing proportions:

x / 1.039 mol Cl₂ (g) = 1 mol NaOCl / 2 mol Cl₂ (g)⇒ x = 0.5195 mol NaOCl

e) convert 0.5195 mol NaOCl to grams:

molar mass NaOCl = 22.99 g/mol + 16.00 g/mol + 35.453 g/mol = 74.443 g/molmass = number of mol × molar fixed = 0.5195 mol × 74.443 g/mol = 38.67 g

That should be rounded to 3 far-reaching figures (such as the fixed of belach is given: 22.0 g)

Theoretical yiedl that NaOCl = 38.7 g

f) calculate the percent yiled:

Percent productivity = (actual productivity / theoretical yield) × 100Percent productivity = (22.0 g / 38.7 g) × 100 = 56.8%


Zinc is reduced.

The oxidation number of chlorine does no change.

Aluminum is oxidized.

Explanation:

For the reaction:

2AI(s) + 3ZnCI₂(g) → 3Zn(s) + 2AICI₃(aq).

For the aspects in the reactants side:

Al has actually (0) oxidation state and also converted to (+3) oxidation state in the products (AlCl₃), which method Al is oxidized and also it is the reduce agent.

So, we can check that: Aluminum is oxidized.

Zn has actually the oxidation state (+2) in the reactants side (ZnCl₂) and converted to (0) in the commodities side (Zn), which way that Zn is reduced and also it is the oxidizing agent.

So, us can check that: Zinc is reduced.

and have the right to not check: Zinc is the to reduce agent.

The oxidation state the Cl does not change, it is the same in both political parties (-1).

So, we have the right to check: The oxidation number of chlorine does not change.

and deserve to not check: Aluminum atoms transfer electrons to chlorine atoms.

So, the choices will be:

Zinc is reduced.

The oxidation number of chlorine does not change.

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Aluminum is oxidized.


Answer is: A. Magnesium has actually a 2+ oxidation number and also chlorine has actually a 1- oxidation number. Magnesium is steel from second group of regular table of elements and it shed two electrons to have actually electron configuration together closest noble gas neon (₁₀Ne), chlorine is nonmetal native 17. Group of routine table and it benefit one electron to have electron configuration together argon (₁₈Ar).
B. Is the exactly answer of her question