**Factors the 24** are basically the number that divide it same or specifically without leaving any kind of remainder i.e if a number divides 24 through a remainder that zero, then the number is called a factor.

**All Factors:**1, 2, 3, 4, 6, 8, 12 and also 24.

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**Prime factors:**2, 3.

**Factors in pairs:**(1,24), (2,12), (3,8), (4,6),(6,4),(8,3),(12,2).

**Prime administer of** 24

**Prime factorization** is a technique of “**expressing**” or **finding **the given number together the product of prime numbers. If a number occurs more than once in element factorization, the is usually expressed in exponential type to do it much more compact.

The **prime administer **comes out to be**:** **2 × 2 × 2 × 3 = 23× 3**.

### Prime administrate of 24 by Upside-Down department Method

**Upside-Down department **is one of the methods used to execute the prime factorization of various numbers.

In this method, you will certainly divide a provided “composite” number evenly by the numerous prime numbers(starting native the smallest) till it gets a element number.

It is referred to as **Upside-Down Division** because the prize is flipped upside down.

Here, 24is an even number. So that is certainly divisible by 2 v no remainder.Thus, 2 is its smallest prime factor.

And we get 24÷ 2 = 12. Now find the prime determinants of the obtained quotient.

Repeat step 1 and also Step 2 till we get a result of prime number as the quotient. Here, 12is the quotient.

12÷ 2 = 6. Here, 6 is the quotient.Now find the prime components of the 6.

6÷ 2= 3. Here, 3 is the element number.

So we deserve to stop theprocess.

So, **prime factorization through upside-down department method** comes the end to be:2× 2× 2× 3 = (2^3 imes 3).

**Prime administrate of24 by factor Tree Method**

The** element tree method** is another an approach for developing the element factorization and also all determinants of a offered number.

**To use this an approach for a number x**,

Firstly take into consideration two factors say **a,b** that x such that a*b is equal to x and also at the very least one of lock (a, b) is a prime variable say a.

Then think about two determinants of b to speak c, d such that again at the very least one of them is a prime factor. This process is recurring until both the components are element i.e if we obtain both the factors as element at any kind of step, we protect against the process there.

Following is the aspect tree of the offered number.

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Here we can obtain the prime factorisation that 24 together 2 * 2 * 2 * 3 and also the two prime determinants are 2, 3

## FAQs

**What is the sum of the factors of 24?**

Sum of all components of the required number = (23 + 1 – 1)/(2 – 1) × (31 + 1 – 1)/(3 – 1) = 60

**What room the common Factors the 24 and also 21?**

Since, the determinants of 24 are 1, 2, 3, 4, 6, 8, 12, 24 and also the components of 21 space 1, 3, 7, 21.Hence, <1, 3> are the typical factors the 24 and 21.